Actually any String which could be converted to a primitive can be converted to it, by using the parseXxx() method, where Xxx will replace the type in which it is to be converted, like int, float, etc.
I have provided a sample Java Code which asks the user to enter a number, which is taken as a String by the application. Later it is converted to an integer by using the parseInt() method. Go through the code for a clear understanding on how it is to be used.
package developer;
import java.util.Scanner;
public class StringToInt {
public static void main(String[] args) {
System.out.println("Enter a number which would be taken as a String by the application");
Scanner scanStr = new Scanner(System.in);
String numStore = null;
int numConvert = 0;
// Takes the input as a String
if (scanStr.hasNext()) {
numStore = scanStr.next();
}
// Convert the String to int by using the Integer.parseInt() method
numConvert = Integer.parseInt(numStore);
System.out.println("The number entered by you is: " + numConvert);
}
}
import java.util.Scanner;
public class StringToInt {
public static void main(String[] args) {
System.out.println("Enter a number which would be taken as a String by the application");
Scanner scanStr = new Scanner(System.in);
String numStore = null;
int numConvert = 0;
// Takes the input as a String
if (scanStr.hasNext()) {
numStore = scanStr.next();
}
// Convert the String to int by using the Integer.parseInt() method
numConvert = Integer.parseInt(numStore);
System.out.println("The number entered by you is: " + numConvert);
}
}
The output is something like as shown below.
Enter a number which would be taken as a String by the application
22
The number entered by you is: 22
22
The number entered by you is: 22
Some observation points are:-
The String which is to be converted to a number must be a number in the String format. This is required so that the Java parser can parse the String successfully into an int.
If the value entered is not a number, suppose that you entered a String in words in place of a number in String format, then the output is shown below:-
Enter a number which would be taken as a String by the application
Conversion from String to int
Exception in thread "main" java.lang.NumberFormatException: For input string: "Conversion"
at java.lang.NumberFormatException.forInputString(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source)
at developer.StringToInt .main(StringToInt .java:20)
Conversion from String to int
Exception in thread "main" java.lang.NumberFormatException: For input string: "Conversion"
at java.lang.NumberFormatException.forInputString(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source)
at developer.StringToInt .main(StringToInt .java:20)
So we see that if a String is entered to be parsed as an int, then the Java Compiler gives a big fat "NumberFormatException".
I hope the Java Code provide to convert an a String to an int was helpful. Do leave a comment if you liked the article. Java Code Online will soon be back with another interesting Java article.
Related Java Codes:-
Convert int to String in Java
Convert int to String in Java using Wrapper Classes
0 komentar:
Posting Komentar